Gradient of x + 2y = 3
x + 2y = 3;
2y = -x + 3
y = - $\frac{x}{2}$ + $\frac{3}{2}$;
$m_1 \; = - \frac{1}{2}$
For perpendicular lines
$m_1m_2$ = -1, equation of the
perpendicular from (3,5) is
$\frac{y-5}{x-3}$ = 2
y = 2x - 6 + 5;
y = 2x - 1
johnmulu answered the question on June 13, 2017 at 09:39
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