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A straight line through the point A(2,1) and B(4,n) is perpendicular to the line whose equation is 3y + 2x - 5 = 0. Determine the value of n.

A straight line through the point A(2,1) and B(4,n) is perpendicular to the line whose equation is 3y + 2x - 5 = 0. Determine the value of n.

Answers

0 gradient of the line

3y + 2x - 5 = 0 is 3y = -2x + 5

y = -$\frac{2}{3}x$ + $\frac{5}{3}$

gradient of the other perpendicular line

through A(2,1) is $\frac{3}{2}$

therefore = $\frac{n-1}{4-2}$ = $\frac{3}{2}$

2n - 2 = 6;

2n = 8

n = 4

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johnmulu answered the question on June 13, 2017 at 11:29

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