Find the equation of the line which is perpendicular to the line

Find the equation of the line which is perpendicular to the line 8x + 2y -3 = 0 and has the same x - intercept as the line.

Answers

Gradient of the line

8x + 2y - 3 = 0;

2y = -8x + 3

y = -4x + $\frac{3}{2}$

$m_1= -4; m_2 = \frac{1}{4}$

At x -intercept y = 0

8x = 3;

x = $\frac{3}{8}$


point is ($\frac{3}{8}$,0);

Equation is

$\frac{y}{x-\frac{3}{8}}$ = $\frac{1}{4}x$ - $\frac{3}{32}$

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johnmulu answered the question on June 13, 2017 at 11:53

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