Find the angle between the vectors u=2i+2j and v=3i-2j.correct to one decimal place

      

Find the angle between the vectors u=2i+2j and v=3i-2j.correct to one decimal place

  

Answers


Nicholas
Dot product is given by u.v
=(2*2)+(2*(-3))
=2
Now u.v=|u||v|Cos theta
where theta= angle between
2=(v2²+2²)*(v(3²)+(-2²)Cos theta
Cos theta= 0.1961161
theta= 78.7°
The angle between is 78.7°
Dckwach answered the question on March 26, 2019 at 22:00


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