An oxide of copper in a porcelain boat was reduced by a stream of hydrogen. The results obtained were as follows. Mass of porcelain boat=4.5g Mass of...

      

An Oxide of copper in a porcelain boat was reduced by a stream of hydrogen. The results obtained were as follows.
Mass of porcelain boat=4.5g
Mass of boat + Oxide=6.40g
Mass of boat + Copper=6.02g
(i)Determine the empirical formula of the oxide.
(ii)If the relative formula mass of the oxide is 80,determine its chemical formula.
(Cu =64, O=16)

  

Answers


Seline
(i)
Mass of oxide=6.40g-4.50g=1.9g
Mass of metal=6.02g-4.5g=1.52g
Mass of oxygen=1.9g-4.5g=0.38g
Cu O
Mass 1.52 0.38
Molar mass 64 16
Moles 0.02375 0.002375
Mole ratio 1 1
E.F.=CuO


(ii)(64+16)n=80
n=1
Chemical formula=CuO

Belan answered the question on February 13, 2019 at 09:59


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