Two towns P and Q are 580km apart.A bus left P at 6.10a.m.and maintains an average speed of 90km/hr between P and Q.A car starts...

      

Two towns P and Q are 580km/hr apart.A bus left town P at 6.10a.m. and maintains an average speed of 90km/hr between P and Q. A car starts from Q at 8.00a.m. and travelled towards P at an average speed of 120km/hr.The car stopped for a total of 30 minutes on the way before meeting the bus.
(a)(i)How far from town P did they meet?
(ii)At what time did they meet?
(b)A rally driver starts from town Q towards town P at 9.30a.m.If he averages 180km/hr,calculate;
(i)The distance from Q when the rally driver overtook the car.
(ii)The time when the rally driver overtook the car.

  

Answers


Seline
(a)(i)8.20-6.10=2hrs 10mins
Bus 2,1/6×90=195km

580-195=385km
Rs=120+90=210km/h
T RD/RS=385/210=1,5/6hrs
Distance 15/6×90=165km
From P=165+195=360km

(ii)8.20+1.50=10.10 a.m.

(b)(i)9.30-8.20=1hr10min=1,5/6hrs
Car D=1,1/6×120=140km
R.S.=180-120=60km/hr
T D/RS=140/60=2,1/3hrs
Distance from Q
2,1/3×180=420km

(ii)9.30 + 2.20=11.50a.m.
Belan answered the question on February 25, 2019 at 14:05


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