Get premium membership and access questions with answers, video lessons as well as revision papers.

A metre rule is pivoted at the 20cm mark and it hangs at the 90cm mark from a spring balance 75g wt. Where is the...

      

A metre rule is pivoted at the 20cm mark and it hangs at the 90cm mark from a spring balance 75g wt. Where is the centre of gravity of the metre rule if it weighs 125g?

  

Answers


ODUYA
Clockwise moments = Anticlockwise moments
Moment=force X distance

Force= (75/1000)X10=0.75N

Force= (125/1000)X10=1.25N
-Let y be the distance between pivot and centre of gravity of the metre rule.
-Distance between the pivot and the supporting spring is 90-20=70cm.

Hence

0.75x70=1.25xy


52.5 = 1.25y

y = 52.5/1.25

y = 42 cm

Position of center of gravity is 20+42 =62

C.o.g = 62 cm mark.


ODUYA VIVIAN answered the question on March 9, 2019 at 08:00


Next: 1(a)(i)Define the term rock. (ii)Outline the steps necessary for the formation of mechanically formed sedimentary rocks. (b)Explain three ways metamorphic rocks are formed. (c)State four conditions necessary for...
Previous: Eleza maudhui yanayodhihirika katika tamthilia kigogo

View More Physics Questions and Answers | Return to Questions Index


Learn High School English on YouTube

Related Questions