A farmer was asked to apply fertilizers as follows: 60 kg/ha nitrogen (top dressing) 60 kg/ha P205 (in planting hole). 60 kg/ha K20. How much sulphate of ammonia...

      

A farmer was asked to apply fertilizers as follows:

60 kg/ha nitrogen (top dressing)
60 kg/ha P205 (in planting hole).
60 kg/ha K20. How much sulphate of ammonia (20%) would be required per hectare? How much double super-phosphate (40%) P2O5would be required per hectare? How much muriate of potash (50% K20) would be required per hectare?

  

Answers


samuel
Answer/Solution

Sulphate of ammonia (SA) which gives 60kg/ha N
60/20 x 100 = 300 kg SA

Double super phosphate (40% P2O5)which gives 60kg/ha P205
60/12 x 100 = 150 kg DSP

Muriate of potash (60% K20) which gives 60kg/hK2O
=60/60 x 100 = 100 kg muriate of potash
lemass answered the question on March 15, 2019 at 19:38


Next: Determination of Fertilizer Rates
Previous: A farmer was asked to apply fertilizers as follows: 200kg/ha of DSP (40% P205 150kg/ha of muriate of potash (60% K20) 150kg/ha of sulphate of ammonia (20% N) How...

View More Agriculture Questions and Answers | Return to Questions Index


Exams With Marking Schemes

Related Questions