A block of metal of mass 0.20kg and temperature 100°C is placed in water of mass 0.42g and temperature 21°C. If the final temperature of...

      

A block of metal of mass 0.20kg and temperature 100°C is placed in water of mass 0.42g and temperature 21°C. If the final temperature of the water is 25°C, calculate the specific heat capacity of the metal. (Neglect heat absorbed by the container,take specific heat capacity of water 4200J/kg k.)

  

Answers


sharon
7. Heat lost by metal = 0.2 × C × (100 - 21)
Heat gained by H2O = 0.42 × 4200 (25 - 21)
0.2 × C × (100 - 21)
0.42 × 4200 × (25 - 21)
0.2 × C × 79 = 0.42 × 4200 × 4
C = 446.58 J/ kg
sharon kalunda answered the question on March 25, 2019 at 09:14


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