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In opening a door, the moment exerted about the hinges was 15Nm. If the pushing force was 25N and perpendicular to the door, what is...

      

In opening a door, the moment exerted about the hinges was 15Nm. If the pushing force was 25N and perpendicular to the door, what is the distance of the force from the hinges?

  

Answers


sharon
Moment = force applied × perpendicular distance.
15Nm = 25 N × d
15Nm/25N = d
0.6m = d
sharon kalunda answered the question on March 25, 2019 at 10:08


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