In opening a door, the moment exerted about the hinges was 15Nm. If the pushing force was 25N and perpendicular to the door, what is...

      

In opening a door, the moment exerted about the hinges was 15Nm. If the pushing force was 25N and perpendicular to the door, what is the distance of the force from the hinges?

  

Answers


sharon
Moment = force applied × perpendicular distance.
15Nm = 25 N × d
15Nm/25N = d
0.6m = d
sharon kalunda answered the question on March 25, 2019 at 10:08


Next: Paper chromatography of a plant extract gave the following results. Which Solvent is the most suitable for purifying the extract? Explain.
Previous: A uniform plank of wood is balanced 30cm from one end when a lead of 0.08kg is hung at one end as shown below.

View More Physics Questions and Answers | Return to Questions Index


Exams With Marking Schemes

Related Questions