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Heat absorbed by ice from – 100 = 1x 2,100 x 10 = 2.1 x 104
Heat absorbed by melting ice= 1 x 334 x 104 = 3.34 x 105
Heat absorbed by water from 00 to 1000 = 1 x 4,200 x 100J = 4.2 x 106J
Heat absorbed water at 1000 = ML = 1 x 2,260 x 103 J= 2.26 x 106J.
Total heat absorbed = 301.5 x 104 = 3.035 x 106J
Heat given out by heater = power x time
Time = 3.035 x 106 =
6 x 103
= 0.5025 x 103
= 505 .83s = 8.43min
Wilfykil answered the question on March 26, 2019 at 13:43
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