(i)S
Because oxygen gas is given out at electrode R thus electrode R is the anode since OH- ions which give oxygen migrate
there.
(ii)4OH-(aq) ……………………>2H2O(l) + O2(g) + 4e-
(iii)A brown solid is deposited on electrode S – this is because the CU2+ ions in solution gain electrons at S to form Copper metal as shown in the following equation.
CU2+(aq) + 2e-……………………>CU(s) brown
sharon kalunda answered the question on March 28, 2019 at 08:51
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