25.0cm3 of 0.12M potassium hydroxide solution required 30.0cm3 of a solution of a dibasic acid (H2Y) for complete neutralization. The acid contained 3.15g per 500cm3...

      

25.0cm3 of 0.12M potassium hydroxide solution required 30.0cm3 of a solution of a dibasic acid (H2Y) for complete neutralization. The acid contained 3.15g per 500cm3 solution.
Calculate:
(a) The molarity of the acid solution
(b) The relative formula mass of the acid.

  

Answers


Kavungya
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Kavungya answered the question on March 28, 2019 at 12:03


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