Butane burns in air according to the equation shown below. 2C4H10(g) + 13O2(g) ----> 8CO2(g) + 10H2O(l) What volume of butane must be burnt in oxygen to...

      

Butane burns in air according to the equation shown below.
2C4H10(g) + 13O2(g) ----> 8CO2(g) + 10H2O(l)
What volume of butane must be burnt in oxygen to give 11g of CO2 at r.t.p?
(Molar gas volume at r.t.p = 24.0L; C = 120; O = 16.0; H = 1.0 )

  

Answers


Kavungya
fig182832019350.png
Kavungya answered the question on March 28, 2019 at 12:50


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