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The fig. below shows a floating object of volume 40,000 cm3 and mass 10g. It is held as shown in water of density 1.25g/cm3 by...

      

The fig. below shows a floating object of volume 40,000 cm3 and mass 10g. It is held as shown in water of density 1.25g/cm3 by a light cable at the bottom so that ¾ of the volume of the object is below the water surface. (Assume that up thrust due to air is negligible)
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Calculate the volume of the object under water. *

  

Answers


sharon
Volume under water = ¾ x 40,000
= 30,000cm3
sharon kalunda answered the question on April 3, 2019 at 15:09


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