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Figure shows a circuit where a battery of emf 4.5V, switches A and B, two capacitors.C1= 0.3 µF and C2 = 0.5 µF and a...

      

Figure shows a circuit where a battery of emf 4.5V, switches A and B, two capacitors.C1= 0.3 μF and C2 = 0.5 μF and a voltmeter are connected.
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a) Determine the charge on C1 when switch A is closed and switch B is open
b) What is the effective capacitance CT when both switches A and B are closed?

  

Answers


sharon
a) Q1 = CV = 0.3 F X 4.5 = 13.5c
b) CT = C1 + C2
(0.3 + 0.5) F= 0.8F
sharon kalunda answered the question on April 5, 2019 at 12:52


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