Mass by percentage: C=64.9%,H=13.5%. C+H+O = 100% which can be translated as 100g. Therefore, O=100% - (64.9+13.5)%
=> O = 21.6%. Therefore, C=64.9g, H = 13.5g and O = 21.6g. calculate moles of each element in the compound. This is given by: mass of element/molar mass of element from periodic table. This follows that: C = 64.9/12.0 =5.4083, H = 13.5/1 = 13.5, O = 21.6/16 = 1.35. Then divide each mole value by the smallest number of moles calculated.
=> From the calculated values, the smallest is 1.35. So...> C = 5.4083/1.35 = 4.0061 rounded off to 4, H = 13.5/1.35 = 10, O = 1.35/1.35 = 1. Thus (a) Empirical(simplest) formula of P = C4H10O. (b) Molecular formula of P is given by getting the ratio of Empirical formula mass to molecular formula mass i.e 4C+10H+1O....> 4x12+10x1+1x16 = 74. Relative formula mass = 74. 74/74 = 1. so empirical formula = molecular formula in this case, since the multiplying factor (the ratio) is 1.
raphael answered the question on May 13, 2019 at 18:27
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