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- A particle starts from 0 and moves in a straight line so that its velocity V ms-1 after t seconds is given by
v =...(Solved)
A particle starts from 0 and moves in a straight line so that its velocity V ms-1 after t seconds is given by
v = 3t – t2. The distance of the particle from 0 at time t seconds is s metres.
(a) Express s in terms of t and c where c is a constant.
(b) Calculate the time taken before the particle returns to 0.
Date posted: April 24, 2019. Answers (1)
- The gradient function of a curve is given by(Solved)
The gradient function of a curve is given by 
Determine;
(a) the equation of the curve given the curve passes through point (0,3)
(b) the coordinates of the turning point of the curve.
Date posted: April 24, 2019. Answers (1)
- Given the column vectors.(Solved)
Given the column vectors.
express p as a column vector and hence calculate its magnitude to 3 significant figures.
Date posted: April 24, 2019. Answers (1)
- Make x the subject of the equation.(Solved)
Make x the subject of the equation.
Date posted: April 24, 2019. Answers (1)
- Wambua invested Sh. 6400 at 15% per annum compound interest for 3 years. Muinde invested twice that amount at 12.5% per annum simple interest for...(Solved)
Wambua invested Sh. 6400 at 15% per annum compound interest for 3 years. Muinde invested twice that amount at 12.5% per annum simple interest for the same period of time. Find whose investment earned more interest and by how much.
Date posted: April 24, 2019. Answers (1)
- Solve the simultaneous equation.(Solved)
Solve the simultaneous equation.
Date posted: April 24, 2019. Answers (1)
- The figure below shows a circle centre O and AOC is a straight line. PB is a tangent to the circle at and angle PBC...(Solved)
The figure below shows a circle centre O and AOC is a straight line. PB is a tangent to the circle at and angle PBC = 350.
Giving reasons for each answer, find the size of
(a) Angle BDC
(b) Angle ACB
Date posted: April 24, 2019. Answers (1)
- Solve for x in the equation log (x – 1) = log 12 – log (x – 2)(Solved)
Solve for x in the equation log (x – 1) = log 12 – log (x – 2)
Date posted: April 24, 2019. Answers (1)
- (a) Expand and simplify the binomial expression.(Solved)
(a) Expand and simplify the binomial expression.
(b) Use the first four terms of the simplified expression in (a) above to evaluate to 5 significant figures.
(1.98)5.
Date posted: April 24, 2019. Answers (1)
- Under a transformation whose matrix(Solved)
Under a transformation whose matrix
a figure whose area is 2.5cm2 is mapped onto a figure whose area is 10cm2. Find two possible values of a and hence write down two possible matrices for T.
Date posted: April 24, 2019. Answers (1)
- The table below shows the masses of 40 students in a form 4 class.(Solved)
The table below shows the masses of 40 students in a form 4 class.
(a) State the modal class.
(b) Calculate the median mass
Date posted: April 24, 2019. Answers (1)
- The equation of a circle is x2 – 8x + y2 + 12y + 16 = 0.Determine the coordinates of the centre of the circle...(Solved)
The equation of a circle is x2 – 8x + y2 + 12y + 16 = 0.Determine the coordinates of the centre of the circle and its radius.
Date posted: April 24, 2019. Answers (1)
- The number of bacteria in a colony was originally 3 millions. This number doubled itself after every one hour.Calculate the number of bacteria generated in...(Solved)
The number of bacteria in a colony was originally 3 millions. This number doubled itself after every one hour.Calculate the number of bacteria generated in the colony during the 7thhour.
Date posted: April 24, 2019. Answers (1)
- The length and breadth of a metal sheet are measured to the nearest centimetre and recorded as 25cm and 16cm
respectively.(Solved)
The length and breadth of a metal sheet are measured to the nearest centimetre and recorded as 25cm and 16cm
respectively.
(a) Find the maximum possible error in the area of the sheet.
(b) Calculate to one decimal place the percentage error in the area of the sheet.
Date posted: April 24, 2019. Answers (1)
- Triangle PQR has vertices at P (2,3), Q(1,2) and R(4,1), while triangle PIQIRI has vertices PI(-2,3),QI(-1,2), RI(-4,1)(Solved)
Triangle PQR has vertices at P (2,3), Q(1,2) and R(4,1), while triangle PIQIRI has vertices PI(-2,3),QI(-1,2), RI(-4,1)
(a) (i) Draw triangle PQR and PIQIRI on the grid provided.
(ii) Describe fully a single transformation which maps triangle PQR onto triangle PIQIRI.
(b) (i) On the same grid, draw triangle PIIQIIRII the image of PQR under a reflection on the line y + x = 0.
(ii) Describe fully a single transformation which maps triangle PIIQIIRII onto triangle PIQIRI.
Date posted: April 24, 2019. Answers (1)
- P, Q and R are three villages such that PQ = 10km, QR = 8km and PR = 4km are connecting roads.(Solved)
P, Q and R are three villages such that PQ = 10km, QR = 8km and PR = 4km are connecting roads.
(a) Using a scale of 1cm to represent 1km, locate the relative positions of the three villages.
(b) A water tank T is to be located at a point equidistant from the three villages. By construction locate water tank T and measure its distance from R.
(c) Determine the shortest distance from T to the road PQ by construction.
(d) Determine the area enclosed by the roads PQ, QR and PR by calculation.
Date posted: April 24, 2019. Answers (1)
- Triangle PQR is inscribed in the circle. PQ = 7.8cm, PR = 6.6cm and QR = 5.9cm.(Solved)
Triangle PQR is inscribed in the circle. PQ = 7.8cm, PR = 6.6cm and QR = 5.9cm.
Find;
(a) size of angle QPR
(b) the radius of the circle.
(c) the area of the shaded region.
Date posted: April 24, 2019. Answers (1)
- John bought 3 brands of tea; A, B and C. The cost price of the three brands were Sh. 25, Sh. 30 and Sh. 45...(Solved)
John bought 3 brands of tea; A, B and C. The cost price of the three brands were Sh. 25, Sh. 30 and Sh. 45 per kilogram
respectively. He mixed the three brands in the ratio 5:2:1 respectively. After selling the mixture, he made a profit of
20%.
(a) How much profit did he make per kilogram of the mixture?
(b) After one year the cost price of each brand was increased by 10%.
(i) For how much did he sell one kilogram of the mixture to make a profit of 15%?
(Give your answer to the nearest 5 cents)
(ii) What would have been his percentage profit if he sold one kilogram of the mixture at Sh. 45.
Date posted: April 24, 2019. Answers (1)
- The following distribution shows the marks obtained by 82 students in a Mathematics test.(Solved)
The following distribution shows the marks obtained by 82 students in a Mathematics test.
(a) State the modal class.
(b) Calculate to 2 decimal places:
(i) the mean mark.
(ii) the difference between the median and the mean marks.
Date posted: April 24, 2019. Answers (1)
- The figure below is a velocity time graph for a car.(Solved)
The figure below is a velocity time graph for a car.
(i) Find the total distance travelled by the car.
(ii) Calculate the deceleration of the car.
(b) A car left Nairobi towards Eldoret at 7.12 a.m. at an average speed of 90km/h. At 8.22 a.m, a bus left
Eldoret for Nairobi at an average speed of 72km/hr. The distance between the two towns is 348km. Calculate:
(i) the time when the two vehicles met.
(ii) the distance from Nairobi to the meeting place.
Date posted: April 24, 2019. Answers (1)