Describe the reaction of sulphur (VI) oxide with chlorine

      

Describe the reaction of sulphur (VI) oxide with chlorine.

  

Answers


Kavungya
Sulphur (IV) oxide reacts with moist chlorine to form an acidic mixture of sulphuric (VI) acid and hydrochloric acid.
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Explanation:
- Sulphur (IV) oxide serves as the reducing agent reducing chlorine into hydrochloric acid;
- Chlorine acts as the oxidizing agent; oxidizing the sulphur (IV) oxide into sulphuric (VI) acid
Kavungya answered the question on April 29, 2019 at 13:11


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