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Describe the reaction of sulphur (VI) oxide with chlorine

Describe the reaction of sulphur (VI) oxide with chlorine.

Answers

Sulphur (IV) oxide reacts with moist chlorine to form an acidic mixture of sulphuric (VI) acid and hydrochloric acid.


Explanation:
- Sulphur (IV) oxide serves as the reducing agent reducing chlorine into hydrochloric acid;
- Chlorine acts as the oxidizing agent; oxidizing the sulphur (IV) oxide into sulphuric (VI) acid

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Kavungya answered the question on April 29, 2019 at 13:11

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