Explain Sulphur (IV) oxide as oxidizing agent.

      

Explain Sulphur (IV) oxide as oxidizing agent.

  

Answers


Kavungya
- It reacts as an oxidizing agent with reducing agents more powerful than itself.
Examples
(a). Reaction with hydrogen sulphide
Procedure
- A test tube of dry hydrogen sulphide gas is inverted into a gas jar full of moist sulphur (IV) oxide, and the gases allowed to mix.
Observation
- Yellow deposits of sulphur is produced.

fig262942019417.png

Explanations:
- H2S is a stronger reducing agent than sulphur (IV) oxide.
- Thus sulphur (IV) oxide acts as an oxidizing agent supplying oxygen to the hydrogen sulphide.
Note
- Dry gases do not react and for this reaction to occur, the gases must be moist or at least one of them.

(b). Reaction with burning magnesium
Procedure
- Burning magnesium is lowered into a gas jar full of sulphur (IV) oxide.
Observation
- White fumes of magnesium oxide and yellow specks of sulphur.
fig272942019419.png
Kavungya answered the question on April 29, 2019 at 13:20


Next: In the figure below OY = 20B, OX = 5/2 OA, OA = a and OB = b
Previous: The frequency table shows masses, to the nearest kilogramme of fish caught by a fisherman in a day.

View More Chemistry Questions and Answers | Return to Questions Index


Exams With Marking Schemes

Related Questions