- In August 2014, a tourist visited Mombasa with 240 sterling pounds which she changed to Kenya Shillings at the rate
of KSh. 112.00 per sterling pound....(Solved)
In August 2014, a tourist visited Mombasa with 240 sterling pounds which she changed to Kenya Shillings at the rate
of KSh. 112.00 per sterling pound. She spent KSh. 1000.00 on accommodation and a half of what remained on
entertainment. The balance she converted to Sterling pounds at the rate of KSh. 113.50 per pound. How many Sterling
pounds did she have left?
Date posted: April 30, 2019. Answers (1)
- Find the length NX in the figure below that PQ = 9cm, PX = 12cm and MX = 15cm.(Solved)
Find the length NX in the figure below that PQ = 9cm, PX = 12cm and MX = 15cm.
Date posted: April 30, 2019. Answers (1)
- A fire engine left the fire station at 9.15 a.m and travelled with an average speed of 64km/h. At 10.10 a.m, an
ambulance left the fire...(Solved)
A fire engine left the fire station at 9.15 a.m and travelled with an average speed of 64km/h. At 10.10 a.m, an
ambulance left the fire station and caught up with fire engine at 11.40 am. Find the average speed of ambulance to the
nearest whole number.
Date posted: April 30, 2019. Answers (1)
- Given that the matrix below is a singular matrix find the possible values of x.(Solved)
Given that the matrix below is a singular matrix find the possible values of x.
Date posted: April 30, 2019. Answers (1)
- Solve for x in the equation given below(Solved)
Solve for x in the equation given below
Date posted: April 30, 2019. Answers (1)
- AB is a diameter of a circle. Given that the coordinates of A and B are (-2,2) and (-2,6) respectively, find the equation of
the circle...(Solved)
AB is a diameter of a circle. Given that the coordinates of A and B are (-2,2) and (-2,6) respectively, find the equation of
the circle in the form ax2 + by2 + cx + dy + e = 0
Date posted: April 30, 2019. Answers (1)
- Expand and simplify (2 – y)5 and use the first four terms to find the approximate value of (1.8)5 to 2 decimal places.(Solved)
Expand and simplify (2 – y)5 and use the first four terms to find the approximate value of (1.8)5 to 2 decimal places.
Date posted: April 30, 2019. Answers (1)
- Points P(2,3) and Q (4,5) are mapped into P1(12,14) and Q1 (22,24) respectively by a transformation matrix T. Find the matrix T.(Solved)
Points P(2,3) and Q (4,5) are mapped into P1(12,14) and Q1 (22,24) respectively by a transformation matrix T. Find the matrix T.
Date posted: April 30, 2019. Answers (1)
- Given that Sin theta =5/13,determine the value of tan (90 - theta) without using a calculator or mathematical tables.(Solved)
Given that Sin theta =5/13,determine the value of tan (90 - theta) without using a calculator or mathematical tables.
Date posted: April 30, 2019. Answers (1)
- The table below shows masses of marbles in a certain lab.(Solved)
The table below shows masses of marbles in a certain lab.
Estimate the median using calculation.
Date posted: April 30, 2019. Answers (1)
- Simplify the fraction.(Solved)
Simplify the fraction.
Date posted: April 30, 2019. Answers (1)
- In the figure below AB is the diameter, CD is a tangent to the circle at B and angle CBE is 200. Calculate the angles
labelled...(Solved)
In the figure below AB is the diameter, CD is a tangent to the circle at B and angle CBE is 200.Calculate the angles
labelled x, y and z.
Date posted: April 30, 2019. Answers (1)
- The sides of a triangle were measured to 1dp as 6.4cm, 7.3cm and 8.2cm respectively. Calculate the percentage error
in its perimeter.(Solved)
The sides of a triangle were measured to 1dp as 6.4cm, 7.3cm and 8.2cm respectively. Calculate the percentage error in its perimeter.
Date posted: April 30, 2019. Answers (1)
- The seventh term of an arithmetic progression is 15 while twice the third is 94. Calculate the first term and the
common difference of the progression.(Solved)
The seventh term of an arithmetic progression is 15 while twice the third is 94. Calculate the first term and the
common difference of the progression.
Date posted: April 30, 2019. Answers (1)
- The velocity of a particle after t seconds is given by V = t2 – 4t + 4m/s. Determine the;(Solved)
The velocity of a particle after t seconds is given by V = t2 – 4t + 4m/s. Determine the;
(a) initial velocity of the particle.
(b) time taken the particle is momentarily at rest.
(c) acceleration of the particle at t = 4.
(d) displacement of the between t = 1 seconds and t = 13 seconds.
Date posted: April 30, 2019. Answers (1)
- A,B,C and D are four schools where B is 84km north of A an C is on a bearing of N650W from A at a...(Solved)
A,B,C and D are four schools where B is 84km north of A an C is on a bearing of N650W from A at a distance of 60km. D
is on a bearing of N200W from C and at a distance of 30km.Use a scale drawing to show relative positions of A,B,C and D using a scale of 1cm to represent 10km.
Find;
(a) the distance and bearing of B from C.
(b) the bearing and distance of D from B.
(c) the bearing of A and D.
Date posted: April 30, 2019. Answers (1)
- The length and the width of a rectangular are (6x-1) and (x – 2) respectively. If the length and width are each
increased by 4cm the...(Solved)
The length and the width of a rectangular are (6x-1) and (x – 2) respectively. If the length and width are each
increased by 4cm the new area is thrice that of the initial rectangle.
The length and the width of a rectangular are (6x-1) and (x – 2) respectively. If the length and width are each
increased by 4cm the new area is thrice that of the initial rectangle.
(a) Find the dimension of the initial rectangle.
(b) By what percentage does the area of the rectangle increase after the change.
(c) What is the difference in size between the length and the width of the initial rectangle.
Date posted: April 30, 2019. Answers (1)
- In the figure below, O is the centre of the circle. Angle AEB = 500, angle EBC = 800 and angle ECD = 300. Giving...(Solved)
In the figure below, O is the centre of the circle. Angle AEB = 500, angle EBC = 800 and angle ECD = 300. Giving reasons
calculate:
(a) Angle CDE
(b) Angle DFE
(c) Obtuse angle COE
(d) Angle ADE
Date posted: April 30, 2019. Answers (1)
- Use a ruler and a pair of compasses only for all construction in this question.(Solved)
Use a ruler and a pair of compasses only for all construction in this question.
(a) Construct qualilateral PQRS such that PQ = 5cm, PS = 5cm and SR = 4.5cm, angle SPQ = 750 and angle PSR=900.
(b) Drop a perpendicular from S to meet line PQ at N. Measure SN and calculate the area of the triangle SPN.
(c) Construct a circle passing through vertices P, Q and R of quadrilateral PQRS. Measure the radius of the circle.
Date posted: April 30, 2019. Answers (1)
- (a) A lamp shade is in the form of a frustum of a cone of diameter 21cm and 28cm. Its height is 10cm.
Calculate the volume...(Solved)
(a) A lamp shade is in the form of a frustum of a cone of diameter 21cm and 28cm. Find it's height if the height of the cone that was cut off is 10cm.
(b)Calculate the volume of the lampshade.
(c) Two circles each of radius 5cm intersects such that the distance between their centres is 6cm. The
length of the common chord joining the two points of intersection is 8cm. Calculate the area of intersection.
Date posted: April 30, 2019. Answers (1)