Find the equation of the tangent at the point (3, 1) to the curve. y = x2 - 4x + 4

      

Find the equation of the tangent at the point (3, 1) to the curve.
y = x2 - 4x + 4

  

Answers


sharon
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sharon kalunda answered the question on May 3, 2019 at 09:02


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