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- Grade A tea is mixed with grade B tea. The cost per kg of grade A is Ksh.60 and that of grade B is Ksh.80....(Solved)
Grade A tea is mixed with grade B tea. The cost per kg of grade A is Ksh.60 and that of grade B is Ksh.80. Find the ratio
in which the two grades should be mixed in order to make a profit of 20% by selling 1kg of the mixture at Ksh.90.
Date posted: May 9, 2019. Answers (1)
- a) Determine the inverse of the matrix(Solved)
a) Determine the inverse of the matrix
b) Hence find the coordinates of the point of intersection of the lines x + 2y = 7 and -y + x = 1
Date posted: May 9, 2019. Answers (1)
- R is partly constant and partly varies as the square of q. When R = 5, q = 1 and R = 21 when q...(Solved)
R is partly constant and partly varies as the square of q. When R = 5, q = 1 and R = 21 when q = 3. Find the value of R
when q = 5
Date posted: May 9, 2019. Answers (1)
- Use logarithms to evaluate(Solved)
Use logarithms to evaluate
Date posted: May 9, 2019. Answers (1)
- PQRS is a trapezium where PQ is parallel to SR. PR and SQ intersect at X, so that SX = kSQ and PX = hPR...(Solved)
PQRS is a trapezium where PQ is parallel to SR. PR and SQ intersect at X, so that SX = kSQ and PX = hPR where k and h
are constants.
Vectors PQ = 3q and PS = s, SR = q
a) Show this information on a diagram.
b) Express vector SQ in terms of s and q
c) Express SX in terms of k, q and s
d) Express SX in terms of h, q and s
e) Obtain h and k
f) In what ratio does X divide SQ ?
Date posted: May 9, 2019. Answers (1)
- A particle starts from rest and moves in a straight line. Its velocity Vm/s is given by V = t2 - 3t + 2, where...(Solved)
A particle starts from rest and moves in a straight line. Its velocity Vm/s is given by V = t2 - 3t + 2, where t is the time in seconds moved from a point O.
Find :
a) i)the velocity when t = 3.
ii) the displacement from O when t = 3.
iii) the acceleration of the particle when t = 3.
b) At what time is the particle momentarily at rest ?
Date posted: May 9, 2019. Answers (1)
- In the figure below, ABC is a tangent to the circle, centre O. DOG is a diameter and angle DGF = 60o, angle DBC =...(Solved)
In the figure below, ABC is a tangent to the circle, centre O. DOG is a diameter and angle DGF = 60o, angle DBC = 48o and angle DFE = 25o. Giving reasons, find the size of angles :
) FED
ii) Obtuse FOB
iii) EBD
iv) BCD
v) OBE
Date posted: May 9, 2019. Answers (1)
- A certain number of people agreed to contribute equally to buy books worth shs.1200 for a school library. Five people
pulled out and so that others...(Solved)
A certain number of people agreed to contribute equally to buy books worth shs.1200 for a school library. Five people
pulled out and so that others agreed to contribute an extra sh.40 each. Their contribution enabled them to raise the
sh.1200 expected.
a) If the original number of people was x, write an expression of how much each was originally going to contribute.
b) Write down the expression of how much each contributed after the five people pulled out.
c) Calculate how many people made the contribution.
d) If the prices of books before buying went up in the ratio 5 : 4 how much extra did each contributor give.
Date posted: May 9, 2019. Answers (1)
- A conical glass contains water to a height of 14cm and has a water surface of radius 12cm. A student wishes to
determine the radius, volume...(Solved)
A conical glass contains water to a height of 14cm and has a water surface of radius 12cm. A student wishes to
determine the radius, volume and surface area of a spherical pebble. When he drops the pebble in the water, the water
level rises by 8cm and its surface on the glass has a radius of 16cm as shown below.
a) Find x
b) Find the volume of the pebble
c) Find the radius of the pebble
d) Find the surface area of the pebble
Date posted: May 9, 2019. Answers (1)
- Three ships P, Q and R are at sea such that ship Q is 400km on a bearing of 030o from ship P. Ship R...(Solved)
Three ships P, Q and R are at sea such that ship Q is 400km on a bearing of 030o from ship P. Ship R is 750km from
ship Q and on a bearing of S60oE from ship Q. Ship Q is 1000km and to the north of an enemy ship S.
a) Taking a scale of 1cm to represent 100km, locate the position of ships P, Q, R and S.
b) Find the compass bearing of :
i) ship P from ship S
ii) ship S from ship R
c) Use the scale drawing to determine
i) the distance of S from P
ii) the distance of R from S
d) Find the bearing of :
i) Q from R
ii) P from R
Date posted: May 9, 2019. Answers (1)
- Line segment AB is given below: Mark point D on line AB produced, such that AD : DB = 7 : -2(Solved)
Line segment AB is given below: Mark point D on line AB produced, such that AD : DB = 7 : -2
Date posted: May 9, 2019. Answers (1)
- A Kenyan bank buys and sells Nigerian neira and Canadian dollar at the following rates.(Solved)
A Kenyan bank buys and sells Nigerian neira and Canadian dollar at the following rates.
Mrs. Emenike, a Nigerian arrived in Kenya with 46,000 neira. She exchanged the whole amount to Kenya shillings and
spent a total of Kenya shillings 720,000. She later changed the remainder to Canadian dollars on her way to Canada.
How much did she receive to 2d.p.
Date posted: May 9, 2019. Answers (1)
- In the figure below, AB is parallel to DE. AB = 10cm, AD = 2cm, BE = 1cm, DC = 3cm.(Solved)
In the figure below, AB is parallel to DE. AB = 10cm, AD = 2cm, BE = 1cm, DC = 3cm.
a) Calculate the lengths of DE and EC.
b) Hence calculate the ratio of the area of DCE : ADEB
Date posted: May 9, 2019. Answers (1)
- Use reciprocal tables to find the reciprocals of 0.4346 and 0.9182.Hence, evaluate
(Solved)
Use reciprocal tables to find the reciprocals of 0.4346 and 0.9182.Hence, evaluate
Date posted: May 9, 2019. Answers (1)
- Two churches have a total of 500 members, the difference between members of the two churches is 200. How many
members are there in each church...(Solved)
Two churches have a total of 500 members, the difference between members of the two churches is 200. How many
members are there in each church ?
Date posted: May 9, 2019. Answers (1)
- The angle of elevation of the top of a tree from a boy’s eye positioned at point A is 20o. The boy moves 100 metres
closer...(Solved)
The angle of elevation of the top of a tree from a boy’s eye positioned at point A is 20o. The boy moves 100 metres
closer to the tree and the angle of elevation becomes 32o. Find the height of the tree. (Disregard the height of the boy)
Date posted: May 9, 2019. Answers (1)
- Write down the three inequalities which define the region R.(Solved)
Write down the three inequalities which define the region R.
Date posted: May 9, 2019. Answers (1)
- The figure below represents a net with a path marked on it, drawn accurately.(Solved)
The figure below represents a net with a path marked on it, drawn accurately.
a) What solid does the net represent?
b) Draw the solid and clearly show the path.
Date posted: May 9, 2019. Answers (1)
- Solve for x and y in the equation.(Solved)
Solve for x and y in the equation.
Date posted: May 9, 2019. Answers (1)
- A line P has its x and y intercept as -2 and -3 respectively.(Solved)
A line P has its x and y intercept as -2 and -3 respectively.
a) Find the gradient of line P.
b) Line Q passes through (5, -2) and is parallel to line P. Write the equation of line Q in the form y = mx + c
Date posted: May 9, 2019. Answers (1)