(a) M – Oxygen
N – Hydrogen
(b) 4OH-(aq)-----> 2H2O(l) + O2(g) + 4e
(c ) Cathode, since H+ which has an oxidation number of +1 is reduced to H2
which has an oxidation number of O.
(d) Platinum / graphite since they are inert and therefore do not react with the
electrolyte or the products.
sharon kalunda answered the question on May 17, 2019 at 09:30
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