What is the angle of line whose equation is 3x+y=0 in cartesian plane.

What is the angle of line whose equation is 3x+y=0 in cartesian plane.

Answers

3x+y=0
This means y=-3x where the coefficient of x when the equation is written in the form of y=mx +c is usually the gradient. Thus the gradient of this line is -3.
The angle this line it makes with x-axis is the tan inverse of gradient and in this case is tan inverse of -3 which is -71.565.
Therefore this line makes an angle of 71.565 degrees with the x-axis.

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joseph kieti answered the question on September 15, 2017 at 18:45

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