Every time an insect jumps forward the distance covered is half of the previous jump. If the insect initially jumped 8.4cm, calculate (i) To the nearest two...

      

Every time an insect jumps forward the distance covered is half of the previous jump.
If the insect initially jumped 8.4cm, calculate
(i) To the nearest two decimal places distance of the sixth jump
(ii) The total distance covered after the sixth jump

  

Answers


Kavungya
i) d = 8.4 r = ½
6th jump = 8( ½ )6-1
8.4/32
= 0.2625 = 0.26cm
ii) 56 = 9.4 (1 – ( ½ ) 6
1 – ½
= 8.4 x 63 x 2
64
= 16.54 cm
Kavungya answered the question on June 18, 2019 at 11:28


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