a)The amount of substance discharged at the electrodes is directly proportional to the quantity of electricity passed.
b)(Au =197)
Au3+ (aq) + 3e- ------------>Au(s)
1 F=96500
3F= 96500×3=289500 C
289500=197
=2.5
(2.5 ×289500)/197=3673.86 C
Q=It=3673.86=2.5×t
t=(1469.59)/60
=24.49 mins
c)i.Al(s) // Al(aq) // Cu+(aq // Cu (s)
ii)Anode- Al(s)------------>Al3+ (aq) +3e-
Cathode - Cu+ + e- ------------->Cu(s)
iii)Emf= EReduced - EOxidised
0.52- -1.66= +2.18V
iv)Al(s)+ 3Cu+(aq -------> Al3+(aq) + 3Cu (s) +2.18
d)Ag+(aq) + e- --------------->Ag (s)
Githiari answered the question on September 14, 2017 at 20:26
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