Sodium thiosulphate solution reacts with dilute hydrochloric acid according to the following equation. S₂O₃^2- (aq) + 2H+ (aq) ---> H₂O (l) + SO₂ + S(s) In an experiment...

      

Sodium thiosulphate solution reacts with dilute hydrochloric acid according to the
following equation.
S₂O₃^2- (aq) + 2H+ (aq) ---> H₂O (l) + SO₂ + S(s)
In an experiment to study how the rate of reaction varies with concentration,
10cm³ of 0.4M sodium thiosulphate was mixed with 10cm³. Of 2M hydrochloric acid in a
flask. The flask was placed in a white paper marked with across X.The time taken for the
cross X become invisible when viewed from above was noted and recorded in the table
below. The experiment was repeated three times as the temperature using the volumes in
the table and the results recorded as shown in the table below.

a) i) On the grid below, plot a graph of the volume of thiosulphate (Vertical
axis) against time taken for the cross (X) to become invisible)
ii) From the graph determine how long it would take for the cross to become
invisible if the experiment was done.
i) Using 6cm³ of the 0.4M thiosulphate
ii) Using 6cm³ of 0.2M thiosulphate solution
b) i) Using values for experiment I.Calculate
i) Moles of thiosulphate used
ii) Moles of hydrochloric acid used
ii) Explain which of the two reactants in experiment I controlled the rate of
the reaction? Explain
c) Give two precautions which should be taken in experiment I controlled the rate of
the reaction? Explain

  

Answers

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Kavungya answered the question on June 22, 2019 at 06:17

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