Potassium sulphite solution was prepared and divided into two portions. The first portion gave a white precipitate when reacted with barium nitrate. On addition of dilute hydrochloric...

Potassium sulphite solution was prepared and divided into two portions. The first
portion gave a white precipitate when reacted with barium nitrate. On addition of
dilute hydrochloric acid the white precipitate disappeared.
a) Write the formula of the compound which formed as the white precipitate.
b) Write the equation for the reaction between dilute hydrochloric acid and
the compound whose formula is written in (a) above.
c) What observation would be made if one drop of potassium dichromate
solution was added to the second portion followed by dilute hydrochloric
acid?

Answers

(a) - Barium Sulphate (BaSO₃)
(b) - BaSO₃(s) + 2HCI (aq)---> BaCI₂(aq) + SO₂(aq)
(c) - Changes from orange to green

Kavungya answered the question on June 22, 2019 at 06:42

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