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When excess lead nitrate solution was added to a solution containing sodium chloride, the precipitate formed was found to weigh 5.56 g. Determine the amount of...

      

When excess lead nitrate solution was added to a solution containing sodium chloride,
the precipitate formed was found to weigh 5.56 g. Determine the amount of sodium
chloride in the solution ( Pb = 207, Cl = 35.5 Na = 23)
PbXO3(aq) + 2NaCl (aq) → PbCI2 + NaNO3 (aq) (l)

  

Answers


Kavungya
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Kavungya answered the question on June 24, 2019 at 07:10


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