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A meter rule is balanced by masses of 18g and 12g suspended from its ends. Find the position of its pivot point.

      

A meter rule is balanced by masses of 18g and 12g suspended from its ends. Find the position of its pivot point.

  

Answers


Davis
18 x =12(100-x)
18 x =1200-12x
30x=1200
x=40cm
The pivot is 40cm from 18g mass or 60cm mark from the 12g mark.

Githiari answered the question on September 16, 2017 at 07:39


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