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Heat gained by calorimeter
= 60 x 10-3 x 378 ( 45 – 25) J;
= 453.6 J
Heat gained by water
= 100 x 10-3 x 4.200 ( 45 – 25J;
= 8.400J
Heat lost by condensing steam = m/
( 163.5 – 160 ) x 10^-3/J
= 3.5 x 10^-3 x / J
Heat lost 3.5 g of ( condensed steam) water cooling to 45^0C
3.5 x 10^-3 ( 100 – 45) x 4,200;
= 808.5J
Heat given = heat gained
Hence:
3.5 / x 10^-3 + 808.5 J = 453 6J + 8,400J;
= 2.3 x 10^-6 J/Kg;
Githiari answered the question on September 19, 2017 at 07:09
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