In an experiment, iron was heated in the presence of excess oxygen and the following data was obtained.

      

In an experiment, iron was heated in the presence of excess oxygen and the following data was obtained:

Mass of empty crucible = 10.98 g

Mass of crucible + iron before reaction = 12.66 g

Mass of crucible + iron after heating = 13.30 g

Calculate the empirical formula of the oxide of iron. (Fe =56, O = 16)

  

Answers


Maurice
Mass Fe = 12.66 – 10.98 = 1.68

Mass of O = 13.30 – 12.66 = 0.64

Moles Fe = 1.68/56 = 0.03

Moles O = 0.64/16 = 0.04

Mole ratio Fe:O = 1: 1.3 = 3:4

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maurice.mutuku answered the question on August 14, 2019 at 13:27


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