For the circuit shown in Fig. 4.38 (i), draw the d.c. load line.

For the circuit shown in Fig. 4.38 (i), draw the d.c. load line.

Answers

The collector-emitter voltage V_CE is given by ;
V_CE = V_CC - I_CR_C ...(i)

When I_C = 0, then,
V_CE = V_CC = 12.5 V
This locates the point B of the load line on the collector-emitter voltage axis.

When V_CE = 0, then,
I_C = V_CC/R_C = 12.5 V/2.5 kilo-ohms = 5 mA
This locates the point A of the load line on the collector current axis. By joining these two points, we get the d.c. load line AB as shown in Fig. 4.38 (ii).

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Wilfykil answered the question on August 15, 2019 at 06:27

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