A line Ax +3y-6=0 is perpendicular to the line 5x+7y-k=0.

      

A line Ax +3y-6=0 is perpendicular to the line 5x+7y-k=0. If 5x+7y-k=0 passes through the point (4,3). Determine the values of A and K

  

Answers


Wilfred
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Wilfykil answered the question on September 4, 2019 at 05:27


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