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Sulphur (IV) oxide and nitrogen (IV) oxide reacts as shown in the equation below.

      

Sulphur (IV) oxide and nitrogen (IV) oxide reacts as shown in the equation below.
SO2 + NO2----->SO3(g) + NO(g)
(a) Using oxidation numbers show that this is a redox reaction.
(b) Identify the reducing agent.

  

Answers


Maurice
(a) SO2(g) + NO2(g)----->SO3(g) + NO(g)
N + (-2 x 2) = 0 S + (-2 x 3) = N + (-2) = 0
S + (-2 x 4) = 4) N = 4 S = +6 N = +2
S = +4

O.N of S increased from +4 to +6 – Oxidation
O.N of N decreased from +4 to +2 – Reduction

(b) SO2
maurice.mutuku answered the question on September 16, 2019 at 06:12


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