A stone is thrown vertically upwards from Point O. After t seconds the stone is S metres fromO. Given that S = 29.4t...

      

A stone is thrown vertically upwards from Point O. After t seconds the stone is S metres from O. Given that S = 29.4t – 4.9t², find the maximum height reached by the stone.

  

Answers

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S = 29.4t – 4.9t²
ds = 29.4 – 9.8t
dt
At maximum height velocity = 0
0 = 29.4 – 9.8t
9.8t = 29.4
t = 3
29.4(3) – 4.9(9) = 88.2 – 44.1
= 44.1 metres

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Kavungya answered the question on September 20, 2019 at 08:13

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