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Let r represent the radius of the circle and L the length of the arc, ? the angle subtended at the centre of the circle.
L = (?/360)2pr
=(60/360) x 2 x (22/7) x 14
=(44/3)cm^2
Let r represent the radius of the circle and L the length of the arc, ? the angle subtended at the centre of the circle and A the area of the sector.
A = (?/360)pr^2
= (60/360) x (22/7) x 14^2
=(308/3)cm^2
joseph rimiru answered the question on September 23, 2017 at 03:43
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