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A farmer ploughed 2/7 of his farm in the first week, 3/5 of the remaining in the second week and the rest during the third...

      

A farmer ploughed 2/7 of his farm in the first week, 3/5 of the remaining in the second week and the rest during the third week. What fraction did he plough in the third week?
A 2/7
B 3/7
C 5/7
D 6/35

  

Answers


Dana
In the second week, he ploughed
3/5 × (1 - 2/7 )
3/5 × 5/7 = 3/7
In the first two week he ploughed
2/7 + 3/7 = 5/7
In the third week he ploughed
1 - 5/7 = 2/7
The answer is A
Dana05 answered the question on October 14, 2019 at 14:53


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