- A motorist left Embu for Nairobi, a distance of 240km, at 8.00a.m and travelled at an average speed of 90km/h. Another motorist left Nairobi for...(Solved)
A motorist left Embu for Nairobi, a distance of 240km, at 8.00a.m and travelled at an average speed of 90km/h. Another motorist left Nairobi for Embu at 8.30a.m and travelled at 100km/h. Find:
a)The time they met.
b)How far they met from Nairobi.
Date posted: October 16, 2019. Answers (1)
- The figure below represents a cone of height 12cm and base radius of 9cm from which a similar smaller cone is removed, leaving a conical...(Solved)
The figure below represents a cone of height 12cm and base radius of 9cm from which a similar smaller cone is removed, leaving a conical hole of height 4cm.
a)Calculate:
i) The base radius of conical hole.
ii)The volume, in terms of π of the smaller cone that was removed.
b)i) Determine, slant height of the original cone
ii)Calculate, in terms of π the surface area of the remaining solid after the smaller cone is removed.
Date posted: October 16, 2019. Answers (1)
- Without using a calculator, evaluate, giving your answer as a fraction in its simplest form(Solved)
Without using a calculator, evaluate, giving your answer as a fraction in its simplest form
Date posted: October 16, 2019. Answers (1)
- In the figure below, the tangent ST meets chord VU produced at T. Chord SW passes through the centre O, of the circle and intersects...(Solved)
In the figure below, the tangent ST meets chord VU produced at T. Chord SW passes through the centre O, of the circle and intersects chord VU at X. Line ST = 12cm and UT = 8cm.
a)Calculate the length of chord VU.
b)If WX = 3cm and VX : XU = 2 : 3, find SX.
Date posted: October 16, 2019. Answers (1)
- Triangle A1B1C1 is the image of triangle ABC under the transformation represented by the matrix If the area of triangle A1B1C1 is 140cm2, find...(Solved)
Triangle A1B1C1 is the image of triangle ABC under the transformation represented by the matrix 
If the area of triangle A1B1C1 is 140cm2, find the area of triangle ABC.
Date posted: October 16, 2019. Answers (1)
- Simplify the expression: (Solved)
Simplify the expression:
Date posted: October 16, 2019. Answers (1)
- Use logarithms, correct to 4 decimal places to evaluate.(Solved)
Use logarithms, correct to 4 decimal places to evaluate.
Date posted: October 16, 2019. Answers (1)
- A spherical ball is 15cm in diameter. What is its surface area? (Solved)
A spherical ball is 15cm in diameter. What is its surface area?
Date posted: October 16, 2019. Answers (1)
- Evaluate without using tables or a calculator; (Solved)
Evaluate without using tables or a calculator;
Date posted: October 16, 2019. Answers (1)
- a)Complete the table below to 2 d.p.
b)Draw the graphs of y = cos x and y = sin x – cos x, for 0 =...(Solved)
a)Complete the table below to 2 d.p.
b)Draw the graphs of y = cos x and y = sin x – cos x, for 0 ≤ x ≤ 180
c) Using your graphs:
i) Solve the equation ½ Sin x = Cos x.
ii) State the range of values of x in 0 ≤ x ≤ 180, for which 2 Cos x ≤ Sin x.
iii) Solve the equation
Sin x – 1.25 = Cos x
Date posted: October 12, 2019. Answers (1)
- The velocity, v m/s of a particle after t seconds is given by v = t2 – 2t + 4.
a)i) Using the mid- coordinate rule...(Solved)
The velocity, v m/s of a particle after t seconds is given by v = t2 – 2t + 4.
a)i) Using the mid- coordinate rule with six strips, estimate the distance covered by the particle between t = 1 and t =13 seconds.
ii) Find the exact distance the particle covered between t =1 and t = 13 seconds.
b)Calculate the percentage error arising from the estimate in (a) above.
Date posted: October 12, 2019. Answers (1)
- A and B are two points on the latitude 500N. The two points lie on the longitudes 300E and 1500W respectively
a)Calculate:
i) The distance...(Solved)
A and B are two points on the latitude 500N. The two points lie on the longitudes 300E and 1500W respectively
a)Calculate:
i) The distance in km, from A to B along the parallel of latitude. (take π= 22/7, R = 6370km)
ii) The shortest distance from A to B along the great circle, in nautical miles.
b)An aircraft takes 54 hours to fly between the two points, along the great circle. Calculate its speed in km/h.( take 1nm = 1.853km)
Date posted: October 12, 2019. Answers (1)
- a)Complete the table below for the function y = x3 + 2x2 – 3x – 4, to 1 d.p
b)Draw the graph of y = x3...(Solved)
a)Complete the table below for the function y = x3 + 2x2 – 3x – 4, to 1 d.p
b)Draw the graph of y = x3 + 2x2 – 3x – 4, using the values in the completed table.
c) Using your graph:
i) Solve the equation
x3 + 2x2 – 3x = 4.
ii) Estimate the coordinates of the turning points of the curve.
Date posted: October 12, 2019. Answers (1)
- A triangular piece of land PQR is such that PQ = 100m, PR = 120m and angle QPR = 780.
Calculate :
i) RQ
ii)QRP
iii)Find the area...(Solved)
A triangular piece of land PQR is such that PQ = 100m, PR = 120m and angle QPR = 780.
Calculate :
i) RQ
ii)QRP
iii)Find the area of the land in hectares.
Date posted: October 12, 2019. Answers (1)
- A trapezium ABCD is such that the two parallel sides are of length 18cm and 26cm. AB = 9cm and angle ABC = 450. Calculate...(Solved)
A trapezium ABCD is such that the two parallel sides are of length 18cm and 26cm. AB = 9cm and angle ABC = 450. Calculate the area of the trapezium to 1 decimal place.
Date posted: October 12, 2019. Answers (1)
- The end points of a diameter of a circle are P (-3, -9) and Q (7, 15). Determine the equation of the circle in the...(Solved)
The end points of a diameter of a circle are P (-3, -9) and Q (7, 15). Determine the equation of the circle in the form x2+y2+ax+by=c where a, b and c are constants.
Date posted: October 12, 2019. Answers (1)
- Find the equation of the normal to the curve y = 2x3 – 3x2 + 6, when x = 2.(Solved)
Find the equation of the normal to the curve y = 2x3 – 3x2 + 6, when x = 2.
Date posted: October 12, 2019. Answers (1)
- The sixth term of a geometric progression is 16 and the third term is 2. Determine the common ratio and the first term.(Solved)
The sixth term of a geometric progression is 16 and the third term is 2. Determine the common ratio and the first term.
Date posted: October 12, 2019. Answers (1)
- Point R divides line PQ externally in the ratio 4:3. The position vectors of P and Q are 2i + j – 3k and i...(Solved)
Point R divides line PQ externally in the ratio 4:3. The position vectors of P and Q are 2i + j – 3k and i – 2j + k respectively. Find the position vector, of R.
Date posted: October 12, 2019. Answers (1)
- A businessman mixes sugar costing sh. 90 per kg with another type which costs sh.120 per kg. Find the ratio in which the two types...(Solved)
A businessman mixes sugar costing sh. 90 per kg with another type which costs sh.120 per kg. Find the ratio in which the two types should be mixed so that if a kilogram of the mixture is sold at ksh. 147 a profit of 50% is realized.
Date posted: October 12, 2019. Answers (1)