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let x + y = 5 represent equation (1)
let xy = 6 represent equation (2)
from equation (1) x = 5 – y
equation (2) will be y (5 – y) = 6
thus 5y – y^2 = 6
y^2 – 5y + 6 = 0 on factorizing
it will be (y- 3) (y – 2) = 0
thus when y = 3, x =2
thus when y = 2, x = 3
joseph rimiru answered the question on September 24, 2017 at 17:45
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