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Find the radius and centre of a circle whose equation is 2x2 + 2y2 - 16x + 8y +8 =0

      

Find the radius and centre of a circle whose equation is
2x2 + 2y2 - 16x + 8y +8 =0

  

Answers


Kavungya
Dividing through by 2
x2 + y2 – 8x + 4y + 4 = 0
x2 – 8x + y2 + 4y = -4
completing the square on x and y parts
(x – 4)2 + (y + 2)2 = -4 + 16 + 4
(x – 4)2 + (y + 2)2 = 16
Centre (4, -2)
Radius = 4 units
Kavungya answered the question on October 30, 2019 at 06:57


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