Solve for x in the equation. 2sin2x-1 = cos2 x + sin x, where OO = x = 360o.

      

Solve for x in the equation.
2sin2x-1 = cos2 x + sin x, where OO ≤ x ≤ 360o.

  

Answers


Kavungya
2sin2x – 1 = 1 – sin2x + sin x
3sin2x – sin x – 2 =0
(3sin +2) (sin x – 1) = 0
Either sin x=0.6664 or sin = 1
90o 221.80o, 318.19
Kavungya answered the question on November 8, 2019 at 06:28


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