Find the centre and the radius of a circle whose equation is x2 + y2 + 6y - 8x - 2y = 0.

      

Find the centre and the radius of a circle whose equation is x2 + y2 + 6y − 8x − 2y = 0.

  

Answers


Kavungya
X2 - 8x + 16 + y2 + 6y + a = 24 + 16 + 9
(x-4)2 + (y+3)2=49
Center (4,-3)radius 7
Kavungya answered the question on November 18, 2019 at 13:57


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