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An electric pump can raise water from a low level reservoir to the higher – level reservoir at the rate of 3.0 x 10^5 kg...

An electric pump can raise water from a low level reservoir to the higher – level reservoir at the rate of 3.0 x 10^5 kg per hour.The vertical height of the water raised 360m.If the rate of energy loss in form of heat is 200KW, determine the efficiency of the pump.

Answers

Davis
Power Input =(3.0 x 10^5 x 10 x 360)/3600= 3x 10^5 watts.
Total = ( 3 + 2_ x 10^3 = 5.0 x 10^3 kw
Eff. 3/5 x 100 = 60%.
Githiari answered the question on September 25, 2017 at 17:14

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