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Find the equation of the line from the point (-1, 4/3) and perpendicular to the line whose equation is ; y-3x+1=0

      

Find the equation of the line from the point (-1, 4/3) and perpendicular to the line whose equation is; y-3x+1=0

  

Answers


joseph
Rewrite the equation in the form y = m x + c
Y =3x -1
For perpendicular like the product of their gradient is -1
Hence 3xm = -1 where m is the gradient of the other line which is perpendicular to the given one
m =-1/3
so the equation of the line will be
(y – 4/3) = -1/3(x—-1)
Y = (-1/3) x + 7/3

joseph rimiru answered the question on October 2, 2017 at 19:59

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