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A trader sells a bag of beans for sh 2,100 and that of maize for 1,200. He mixed beans and maize in the ratio 3:2. Find how much the trader should sell a bag of the mixture to realize the same profit.

Class: Form 3

Subject: Mathematics

Topic: Compound Proportions and Rates of Work

Lesson Summary

A trader sells a bag of beans for sh 2,100 and that of maize for 1,200. He mixed beans and maize in the ratio 3:2. Find how much the trader should sell a bag of the mixture to realize the same profit.



Text Answer


Solution:
B= 2,100 bag
M=1200 bag
B:M= 3:2

Total cost= 3(2100)+2(1200)
=6300 + 2400
=8700

Let the selling price of the mixture be y
Y(3+2)=8700
5y= 8700
Y=1740

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