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Mary has 21 coins whose total value is sh.72. there are twice as many five shilling coins as there are ten shilling coins. The rest are one shilling coins. Find the number of ten shilling coins that Mary has.

Class: Form 1

Subject: Mathematics

Topic: Linear Equations

Lesson Summary

Mary has 21 coins whose total value is sh.72. there are twice as many five shilling coins as there are ten shilling coins. The rest are one shilling coins. Find the number of ten shilling coins that Mary has.



Text Answer


21 coins value sh. 72

Sh.5 coins = 2x

Sh.10 coins = x

Sh. 1 coins

5(2đť‘Ą)+10đť‘Ą=72
10đť‘Ą+10đť‘Ą=72
20x = 72

The highest number before 72 which is divisible by 20 is 60
20x20=6020

X = 3

3 ten shilling coins.

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